Program 334: Number of Characters need to make a String Palindrome
//Coming Soon
Output:
#include<stdio.h> #include<string.h> main(){ int i=0,j,totChar=0,flag=0,c; char str[100]; printf("Enter a String\n"); scanf("%s",str); int len=strlen(str); j=len-1; while(i<j) { if(str[i]==str[j]) { i++; j--; flag=1; } else { totChar++; i++; flag=0; } } if(flag!=1) totChar=len-1; c=totChar-1; printf("Total Characters required=%d\n",totChar); for(i=0;i<totChar;i++) str[len+i]=str[c--]; str[len+i]='\0'; printf("Final String of Palindrome=%s\n",str); }Explanation:
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Output: